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In what ratio should .(17)CI^(37) and .(...

In what ratio should `._(17)CI^(37)` and `._(17)CI^(35)` be presents so as to obtain `._(17)CI^(35.5)`?

A

`1:2`

B

`1:1`

C

`1:3`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
C
Let `x%` of `CI^(17) `and `(100 - x)%` of` CI^(15)` be presents in `._(17)CI^(35.5)`
`:. 35.5 = (x xx 37 + (100 - x) xx 35)/(100)`
Solve for x,
`x = 25`
`:. % of CI^(37) = 25`
`:. % of CI^(o+) = 75`
`:. Ratio is 1:3`
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