The enrgy of an electron in the first Borh orbit of H atom is `-13.6 eV` The possible energy values (s)of the excited state (s) for electron in bohr orbitsw of hydrogen is (are)

Options

A. `-3.4 eV`
B. `-4.2 eV`
C. `-6.8 eV`
D. `+ 6.8 eV`

Answer

A

Explanation

The energy of an electron in Bohr orbit of hydrogen atom is given by the expeeression
`E_(n) = - (Constant)/(n^(2))`
When n takes only value for the first Bohr orbit `n = 1`and it is gigev that
`E_(1) = -13.6 eV` Hence
`E_(n) = (13.6 eV)/(n^(2))`
Of the given value of energy only `-13.6 eV` can be obtained by substating `n = 2` in the above expression