The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV`. The possible energy values (s) of the excited state (s) for electron in bohr orbits of hydrogen is (are)

Options

A. `-3.4 eV`
B. `-4.2 eV`
C. `-6.8 eV`
D. `+6.8 eV`

Answer

A

Explanation

`E_(n) = (-13.6)/(n^(2))Z^(2)eV`
For `n = 2`, for H atom,
`E = (-13.6)/(2^(2)) 1^(2) eV = - 3.4 eV`
Other value cannot be obtained for `n = 3,4,5,6` etc