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The ratio of energy of photon of lambda ...

The ratio of energy of photon of `lambda = 2000 Å` to that of `lambda = 4000 Å` is

A

2

B

4

C

`1//2`

D

`1//4`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = (hv)/(lambda) , :. (E_(1))/(E_(2)) = (lambda_(2))/(lambda_(1)) = (4000)/(2000) = 2`
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