`5 g` of He at `27^(@)C` is subjected to a pressure change from `0.5 atm` to `2 atm`. The initial volume of the gas is `10 dm^(3)`. Calculate the change in volume of the gas.

Explanation

Given that `P_(1)=0.5 atm`, `P_(2)=2 atm`, `V_(1)=10 dm^(3)`, `V_(2)=?`
Using Boyle's relationship `P_(1)V_(1)=P_(2)V_(2)`, we get
`V_(2)=(P_(1)V_(1))/(P_(2))=(0.5xx10)/(2)=2.5 dm^(3)`
Hence change in volume
`DeltaV=V_(1)-V_(2)=10-2.5=7.5 dm^(3)`