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Draw a graph of log P and log (1//V) for...

Draw a graph of `log P` and `log (1//V)` for a fixed amount of gas at constant temperature.

Text Solution

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According to Boyle's law, `P=log(1//V)+log K`
Comparing it to `y=mx+c`, we find that the graph of `log P vs log (1//V)` should be a straight line with slope equal to `k`, i.e.
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Knowledge Check

  • When the graph of PV v/s P plotted pressure for a given amount of the gas at constant temperature the line obtained is

    A
    Parallel to X-axis
    B
    Parallel to Y-axis
    C
    Linear with positive slope
    D
    Linear with negative slope

  • At low pressure, the graph of PV vs (1)/(V) for a given amount at a constant temperature for a real gas is:

    A
    straight line parallel to x-axis
    B
    straight line having positive intercept and negative slope
    C
    straight line passing through origin having positive slope
    D
    none of the above

  • Graph between P and V at constant temperature is

    A
    straight
    B
    curved increasing
    C
    straight line with slope
    D
    parabolic curve decreasing

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    Which of following graphs correctly represent variation of alpha = (-(dV//dP)_(T))/(V) with P for fixed amount of an ideal gas at constant temperature ?

    Consider the following statements - (i) At same P, if V vs T graph is draw for sam e mass of the two idea gaes, then the heavier has will have a heighter slope. (ii) Intercept of log V vs T graph should always be posiive. (iii) Graph of V^(2) vs (1)/(T^(2)) for fixes amount of an ideal gas at constant pressure will be a parabola.

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