What is the volume of a sample of oxygen at a pressure of `3.5"bar"` if its volume at `1`bar is `3.15 L` at th same temperature?

Explanation

Here, `P_(1)=1"bar"`, `P_(2)= 3.5"bar"`, `V_(1)= 3.15 L`, `V_(2)=?`
From Boyle's law equation `P_(1)V_(1)=P_(2)V_(2)`, we get
`V_(2)=(P_(1)V_(1))/(P_(2))=(1.00 "bar"xx3.15 L)/(3.5 "bar")=0.90 L`