A gas occupies a volume of `2.5 L` at `9xx10^(5)Nm^(-2)`. Calculate the additional pressure required to decrease the volume of the gas to `1.5 L`, Keeping temperature constant.

Explanation

Here,`P=9xx10^(5)Nm^(-2)`, `P_(2)=?`
`V_(1)=2.5 L`, `V_(2)=1.5 L`
From Boyle's law equation `P_(1)V_(1)=P_(2)V_(2)`, we get
`P_(2)=(P_(1)V_(1))/(V_(2))=(9.0xx10^(5)Nm^(-2)xx2.5 L)/(1.5 L)=15xx10^(5)Nm^(-2)`
The additional pressure required is
`15xx10^(5)Nm^(-2)-9xx10^(5)Nm^(-2)=6xx10^(5)Nm^(-2)`