A Vessel of `120 mL` capacity contains a certain mass of gas at `20^(@)C` and `75 mm` pressure. The gas was transferred to a vessel whose volume is `180 mL`. Calculate the pressure of the gas at `20^(2)C`

Explanation

since a gas completely fills the vessel in which it is kept,
we have
`V_(1)=120 mL`, `V_(2)=180 mL`
`P_(1)=750 mm`, `P_(2)=?mm`
Since the temperature remains constant, by applying Boyle's law, we get
`P_(1)V_(1)=P_(2)V_(2)`
Subsitiuting the corresponding values, we have
`750xx120=P_(2)xx180`
or `P_(2)=(750xx120)/(180)=500mm`
Therefore, the pressure of the gas is `500mm`.