A flask having a volume of `250.0 mL` and containing air is heated to `100^(@)C`, immered in water, and opened. What volume of water will be drawn back into the flask, assuming the pressure remaining constant?

Explanation

Let the volume `(V_(1))` of the flask be `250.0 mL`
at temperature `(T_(1))=100+273=373 K`
Flask cooled to temperature `(T_(2))=25+273=298K`
According to Charles's law
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
Hence, the volume `(V_(2))` at `298 K` is `(V_(1)xxT_(2))/(T_(1))`.
`:. V_(2)=(250xx298)/(373)=199.73cm^(3)`
Therefore, water drawn back is `250-199.73=50.27 cm^(3)`