A steel tank contains air at a pressure of `15` bar at `20^(@)C`. The tank is provided with a safety valve which can withstand a pressure of `30"bar"`. Calculate the temperature to which the tank can be safely heated.

Explanation

Let `P_(1)=15"bar"`, `P_(2)= 30"bar"`
`T_(1)=20^(@)C=293 K`, `T_(2)=?`
Now, `(P_(1))/(T_(1))=(P_(2))/(T_(2))` or `T_(2)=(P_(2)T_(1))/(P_(1))=(30xx293)/(15)`
`:. T_(2)=586 K` or `313^(@)C`
Thus, the safety valve will blow up when the temperature exceeds `313^(@)C`.