`20 mL` of hydrogen measured at `15^(@)C` is heated to `35^(@)C`. What is the new volume at the same pressure?

Explanation

`{:("Given conditions","Final conditions"),(V_(1)=20mL, V_(2)=?mL),(T_(1)=15+273=288 K, T_(2)=35+273=308 K):}`
By applying Charles'law, we get
`(V_(2))/(308)=(20)/(288)`
`V_(2)=(20)/(288)xx308=21.38`
The volume of hydrogen gas at `35^(@)C` is `21.38 mL`.