A sample of nitrogen occupies a volume of `320 cm^(3)` at `STP`. Calculate its volume at `546.3 K` and `0.5` bar pressure.

Explanation

Given, `P_(1)=1.0` bar, `P_(2)=0.5` bar
`V_(1)=320cm^(3)`, `V_(2)=?`
`T_(1)=273.15 K`, `T_(2)=546.3 K`
According to gas equation, we get
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`:. V_(2)=(P_(1)V_(1)xxT_(2))/(T_(1)xxP_(2))=(1xx320xx546.3)/(273.15xx0.5)=1280 cm^(3)`