A sample of gas occupies a volume of `320 cm^(3)` at `STP`. Calculate its volume at `66^(@)C` and `0.825atm` pressure.

Explanation

Here,
`P_(1)=1.00 atm`, `P_(2)=0.825 atm`
`V_(1)=320 cm^(3)`, `V_(2)=?`
`T_(1)=273 K`
`T_(2)=66^(@)C=(66+273)K=339K`
According to the gas equation,
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`V_(2)=(P_(1)V_(1)T_(2))/(T_(1)P_(2))=(1xx320xx339)/(273xx0.825)=482cm^(3)`