The drain cleaner Drainex contains small bits of aluminimum which react with caustic soda to form hydrogen. What volume of hydrogen at `20^(@)C` and `1 "bar"` will be released when `0.15 g` of aluminimum reacts?

Explanation

The chemical reaction taking place is
`underset(2xx27 g)underset(2 mol)(2AI)+2NaOH+2H_(2)O rarr 2NaAIO_(2)+underset(3mol)(3H_(2)`
`54 g` of `Al` produces hydrogen `=3 mol`
`0.15 g` of `Al` produces hydrogen
`=(3xx0.15)/(54) mol=8.33xx10^(-3)mol`
Calculation of volume of `8.33xx10^(-3)mol` of hydrogen at `20^(@)C` and `1` bar:
`V=(nRT)/(P)`
`=(8.33xx10^(-3)(mol)xx0.083("bar" L K^(-1) mol^(-1))xx293 (K))/(1 "bar")`
`=0.20282 L=202.82 mL`