The density of a certain gaseous oxide of `1.5"bar"` pressure and `10^(@)C` is same as that of dioxygen at `20^(@)C` and `4.5"bar"` pressure. Calculate the molar mass of the gasesous oxide.

Explanation

Density of dioxygen `(O_(2))` at `4.5 "bar"` pressure and `10^(@)C`
`rho_(O_(2))=(PM)/(RT)=(4.5xx32)/(Rxx283.15)`
`rho_(oxide)=(PM)/(RT)=(1.5xxM)/(Rxx293.15)`
Now, `rho_(O_(2))=rho_(oxide)`
`:. (4.5xx32)/(Rxx283.15)=(1.5xxM)/(Rxx293.15)`
or `M=(4.5xx293.15xx32)/(283.15xx15)=99.39 g mol^(-1)`
Therefore, the molecular mass of oxygen dioxide is `99.39 g mol^(-1)`