The average velocity of `CO_(2)` at the temperature `T_(1)K` and maximum (most) proable velocity of `CO_(2)` at the temperature `T_(2) K` is `9xx10^(4) cm s^(-1)`. Calculate the values of `T_(1)` and `T_(2)`.

Explanation

Given
Average speed=Most proable speed
`=9xx10^(-4)cm s^(-1)` or `9xx10^(2)m s^(-1)`
We know,
Average speed `=sqrt((8RT)/(pi M))` (`i`)
and most probable speed `=((2RT)/(M))` (`ii`)
Equating equations (`i`) and (`ii`), we get
`9xx10^(2)=sqrt((8xx8.314xxT_(1))/(3.14xx44xx10^(-3)))`
or `T_(1)=1682.5 K`
and `9xx10^(2)=sqrt((2xx8.314xxT_(2))/(44xx10^(-3)))`
or `T_(2)=2143.4 K`