`1 mol` of `SO_(2)` occupies a volume of `350 mL` at `300 K` and `50 atm` pressure. Calculate the compressibility factor of the gas.

Explanation

`{:(P=50 atm, V=350 mL=0.350L),(n=1 mol, T=300 K):}`
We know that, `Z=(PV)/(nRT)`
`Z=(50atmxx0.350L)/(1 molxx0.082 L atm K^(-1) mol^(-1)xx300 K)=0.711`
Thus, `SO_(2)` is more compressible than expected from ideal behaviour.