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The internal pressure loss of 1 mol of v...

The internal pressure loss of `1 mol` of van der Waals gas over an ideal gas is equal to

A

Zero

B

`b^(2)`

C

`(a)/(V^(2))`

D

`b-(a)/(RT)`

Text Solution

Verified by Experts

`P+(a)/(V^(2))` is the pressure of the ideal gas, while `P` is the pressure of the real gas. Therefore, `a//V^(2)` is the difference.
Hence, the correct choice is (`c`).
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CENGAGE CHEMISTRY-STATES OF MATTER-Exercises (Ture False)
  1. The internal pressure loss of 1 mol of van der Waals gas over an ideal...

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  2. In the van der Waals equation (P + (n^(2)a)/(V^(2)))(V - nb) = nRT ...

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  3. Kinetic energy of a molecule is zero at 0^(@)C

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  4. A gas in a closed container will exert much higher pressure due to gra...

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  5. The graph between PV vs P at constant temperature is linear parallel t...

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  6. Real gases show deviation from ideal behaviour at low temperature and ...

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  7. In the microscopic model of the gas, all the moleculer are supposed to...

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  8. For real gases, at high temperature Z = 0 small value of a means gas...

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  9. Small value of a means, gas can be easily liqueifed.

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  10. Rate of diffusion is directly proportional to the square root of molec...

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  11. For ideal gases, Z = 1 at all temperature and pressure.

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  12. According to charles's law,

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  13. The pressure of moist gas is higher than pressure of dry gas.

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  14. Gases do not occupy volume and do not have force of attraction.

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  15. The van der Waal equation of gas is (P + (n^(2)a)/(V^(2))) (V - nb)...

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  16. Surface tension and surface energy have different dimensions.

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  17. The plot of PV vs P at particular temperature is called isovbar.

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  18. Equal volume of all gases always contains equal number of moles.

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  19. A gas with a = 0 cannot be liquified.

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  20. The van der waals constants have same values for all the gases.

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  21. All the molecules in a given sample of gas move with same speed.

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