The van der Waals constant `b` of `Ar` is `3.22xx10^(-5) m^(3) mol^(-1)`. Calculate the molecular diameter of `Ar`.

Explanation

Use `b=4xx`volume occupied by the molecules in `1 mol` of a gas
`b=4xxN_(0)xx((4)/(3)pi r^(3))`
`3.22xx10^(-5)=4xx6.023xx10^(23)xx(4)/(3)xx(22)/(7)xxr^(3)`
`r=[(3.22xx10^(-5)xx3xx7)/(4xx6.023xx10^(23)xx4xx22)]^(1//3)`
`=0.1472xx10^(-9)m=0.1472 nm`
`d=2r=0.2944 nm`