Two flasks `A` and `B` have equal volume. `A` is maintained at `300 K` and `B` at `600 K`. While `A` contains `H_(2)` gas, `B` has an equal mass of `CH_(4)` gas. Assuming ideal behaviours for both the gases, answer the following:
Flask containing greater number of molecules

Options

A. `A`
B. `B`
C. Both `A` and `B`
D. None

Explanation

Let `n_(A)` be the amount of `H_(2)` and `n_(B)` be the amount the `CH_(4)`.
We know that
`n_(A)=(m)/(2)`, `n_(B)=(m)/(16)`
where `m` is the mass of the gas of two flasks `A` and `B`
`:. (n_(A))/(n_(B))=(m)/(2)//(m)/(16)=8`
Now, the number of molecules in these flasks are given as
`N_(A)=(m)/(2).N`, `N_(B)=(m)/(16)N`,
where `N` is Avogadro's constant.
`:. (N_(A))/(N_(B))=8`
`implies N_(A)gtN_(B)`