For two gases `A` and `B` with molecular weights `M_(A)` and `M_(B)`, respectively, it is observed that at a certain temperature `T`, the mean velocity of `A` is equal to the `V_(rms)` of `B`. Thus, the mean velocity of `A` can be made equal to the mean velocity of `B`, if

Options

A. `A` is at temperature `T` and `B` is at `T'` such that `TgtT'`
B. Temperature of `A` is lowered to `T_(2)` while `B` is at `T` such that `T_(2) lt T`
C. Both `A` and `B` are raised to a higher temperature
D. Heat energy supplied to `A`

Explanation

Hint: `mu_(av)=sqrt((8RT)/(pi M))` and `mu_(rms)=sqrt((3RT)/(M))`