A quantity of hydrogen gas occupies a volume of `30.0 mL` at a certain temperature and pressure. What volume would half of this mass of hydrogen occupy at triple the initial temperature, if the pressure was one-ninth that of the original gas?

Options

A. `270 mL`
B. `90 mL`
C. `405 mL`
D. `137 mL`

Explanation

`P_(1)V_(1n_(1)RT_(1)`
`P_(2)V_(2)=n_(2)RT_(2)`
`(P_(2)V_(2))/(P_(1)V_(1))=(n_(2)T_(2))/(n_(1)T_(1))`
`(P_(1))/(9P_(1))(V_(2))/(30)=(1)/(2)(n_(1))/(n_(1))(3T_(1))/(T_(1))`
`V_(2)=405 mL`