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O(2) gas at STP contained in a flask was...

`O_(2)` gas at `STP` contained in a flask was replaced by `SO_(2)` under same conditions. The weight of `SO_(2)` will be

A

Equal to that of `O_(2)`

B

Half that of `O_(2)`

C

Twice that of `O_(2)`

D

One-fourth of `O_(2)`

Text Solution

Verified by Experts

`1 mol` of `O_(2)= 1 mol SO_(2)`
`32 g O_(2)=64 g SO_(2)`
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