The van der Waals equation for one mol of `CO_(2)` gas at low pressure will be

Options

A. `(P+(a)/(V^(2)))V=RT`
B. `P(V-b)=RT-(a)/(V^(2))`
C. `P=(RT)/(V-b)`
D. `P=((RT)/(V-b)-(a)/(V^(2)))`

Explanation

`(P+(a)/(V^(2)))(V-b)=RT`
At low pressure, volume is high and `b` may be ignored. So van der Waals equation becomes
`(P+(a)/(V^(2)))V=RT`
Hence, the answer is (`a`).