A gas volume `100 cc` is kept in a vessel at pressure `10.4 Pa` maintained at temperature `24^(@)C`. Now, if the pressure is increased to `105Pa`, keeping the temperature constant, then the volume of the gas becomes

Options

A. `10cc`
B. `100cc`
C. `1 cc`
D. `1000 cc`

Explanation

Given
`V_(1)=100 mL`
`P_(1)=10.4 Pa`
`V_(2)=?`
`P_(2)=105 Pa`
` P_(1)V_(1)=P_(2)V_(2)`
`:. V_(2)=(P_(1)V_(1))/(P_(2))=(105xx100)/(10.4)=10 mL`