A sample of gas occupies `100 mL` at `27^(@)C` and `740 mm` pressure. When its volume is changed to `80 mL` at `740 mm` pressure, the temperature of the gas will be

Options

A. `21.6^(@)C`
B. `240^(@)C`
C. `-33^(@)C`
D. `89.5^(@)C`

Explanation

`V_(1)=100 mL`, `T_(1)=27^(@)C=300 K`
`P_(1)=740`
`V_(2)= 80mL`
`T_(2)=?`
`P_(2)=740 mm`
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`:. T_(2)=(V_(2)xxT_(1))/(V_(1))=(80xx300)/(100)=240 K`
or `T_(2)= -33^(@)C`