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A 10 L box contains 41.4 g of a mixture ...

A `10 L` box contains `41.4 g` of a mixture of gases `C_(x)H_(8)` and `C_(x)H_(12)`. The total pressure at `44^(@)C` in flask is `1.56 atm`. Analysis revelated that the gas mixture has `87%` total `C` and `13%` total `H`. Find out the value of `x`

A

`1`

B

`3`

C

`5`

D

`2`

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the ideal gas law and the information provided about the gas mixture. ### Step 1: Convert the temperature to Kelvin The temperature given is \(44^\circ C\). To convert this to Kelvin: \[ T(K) = T(°C) + 273.15 = 44 + 273.15 = 317.15 \, K \] ...
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