The rate of diffusion of methane is twice that of `X`. The molecular mass of `X` is divided by `32`. What is value of `x` is ?

Options

A. `1`
B. `2`
C. `3`
D. `4`

Explanation

`r_(CH_(4))=2r_(X)`, we know `r=sqrt((1)/("Molecular mass"))`
`:. (r_(CH_(4)))/(r_(X))=sqrt((M_(X))/(M_(CH_(4))implies (2r_(X))/(r_(X))=sqrt((M_(X))/(16))`
or `M_(X)=64`
Given Molecular mass is divided by `32` therefore,
`X=(M_(X))/(32)=(64)/(32)=2`