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For a monatomic gas, kinetic energy = E....

For a monatomic gas, kinetic energy `= E`. The relation with `rms` velocity is

A

`u=((2E)/(m))^(1//2)`

B

`u=((3E)/(2m))^(1//2)`

C

`u=((E)/(2m))^(1//2)`

D

`u=((E)/(3m))^(1//2)`

Text Solution

Verified by Experts

`v_(rms)=sqrt((3RT)/(M))`
`KE(E) "per mole"=(3)/(2)RT`
`RT=(2)/(3)KE`
`v_(rms)=sqrt((3)/(M)xx(2)/(3)KE)`
`=sqrt((2KE)/(M))=((2KE)/(M))^(1//2)`
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