Calculate the maximum work down when pressure on `10g` of hydrogen is reduced from `20` to `1atm` at a constant temperature of `273K`. The gas behaves ideally. Will there be any change in internal energy. Also calculate `q. (R = 2 cal K^(-1) mol^(-1))`

Explanation

`w =- 2.303 nRT log.(P_(1))/(P_(2))`, mole of `H_(2) = (10)/(2)`
`= 2.303 xx (10)/(2) xx 2xx 273 log.(20)/(1) = 8180 cal`
Since the change is taking place at constant temperature, internla enegry will not change, i.e.,
`DeltaU = 0`
`q = DeltaU - w = 0 - 8180 =- 8180cal`