`10g` of argon gas is compressed isothermally and reversibly at a temperature of `27^(@)C` from `10L` to `5L`. Calculate `q, w, DletaU`, and `DeltaH` for this process. `R = 2.0 cal K^(-1) "mol"^(-1), log_(10)2 = 0.30`. Atomic weight of `Ar = 40`.

Explanation

`w =- 2.303 nTR log_(10). (V_(2))/(V_(1))`
`=- 2.303 xx (10)/(40) xx2xx 300 log_(10).(5)/(10)`
`w = 103.991cal`
`DeltaU = 0`
`:. Q = DeltaU - w :. Q =- w =- 103.991 cal`
Also when temperature is constant `P_(1)V_(1) = P_(2)V_(2)` or `PV =` constant
`:. DeltaH = DeltaU +Delta(PV) = 0 +0 = 0`