A system has internal energy equal to `U_(1), 450J` of heat is taken out of it and `600J` of work is done on it. The final enegry of the system will be

Options

A. `(U_(1) +150)`
B. `(U +1050)`
C. `(U_(1) - 150)`
D. None of these

Explanation

To solve the problem, we will use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added to the system (Q) plus the work done on the system (W). The equation can be expressed as:

\[ \Delta U = Q + W \]

### Step-by-step Solution:

1. **Identify Initial Internal Energy**:
The initial internal energy of the system is given as \( U_1 = 450 \, J \).
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