In a thermodynamic process hellium gas obeys the law `T//p^(2//5) =` constant. The heat given `n` moles of `He` in order to rise the temperature form `T` to `2T` is

Options

A. `8RT`
B. `4RT`
C. `16RT`
D. Zero

Explanation

`T = K xx P^(2//5)`
`:. PV = RT = R.K.P^(2//5)` or `P^(3//5) xx V = K` opr `PV^(5//3) = K'`
or `PV^(gamma) = K' (gamma` for `He = 5//3)`
`:.` Process is adiabatic and `DeltaH = 0`.