`2mol` of an idela gas expand reversibly and isothermally at `25^(@)C` from `2L` to `10L`. Calculate the work done by the gas in calories.

Explanation

Given,
`n = 2, T = (273 +25) = 298K, V_(1) = 2L, V_(2) = 10L`
`:. W = 2.303 nRT log_(10)V_(2)//V_(1)`
`= 2.303 xx2xx2xx 298 xx log_(10) 10//2`
`= 2.303 xx 2xx 2xx 298 xx log_(10)5`
`= 2.303 xx 4 xx 298 xx 0.6990`
`= 1918.878 cal`