How much heat will be required to make `2kg` of calcium carbide `(CaC_(2))` according to the following reaction?
`CaO(s) +3C(s) rarr CaC_(2)(s) +CO(g)`
The heats of formations of `caO(s), CaC_(2)(s)`, and `CO(g)` are `-151.0,-14.0`,and `-26.0 kcal`, respectively.

Explanation

`DeltaH^(Theta) = sum Delta_(f)H^(Theta)("products") - sum Delta_(f)H^(Theta) ("reactants")`
` =[Delta_(f)H_((CaC_(2)))^(Theta)+Delta_(f)H_((CO))^(Theta)-[Delta_(f)H_((CaO))^(Theta)+3Delta_(f)H_((C))^(Theta)]`
`=[1-14.0 - 26.0] -[-151.0+3 x0]`
`=-40.0 + 151.0 = 111.0 kcal`
For formation of `64g` of `CaC_(2) 111.0 kcal` of heat is required. So heat required for making `2000g` of
`CaC_(2) = (111.0)/(64) xx 2000 = 3468.75 kcal`