Calculate `DeltaH` at `85^(@)C` for the reaction:
`Fe_(2)O_(3)(s) +3H_(2)(g) rarr 2Fe(s) +3H_(2)O(l)`
The data: `DeltaH_(298)^(Theta) =- 33.0 kJ mol^(-1)` and `{:("Substance",Fe_(2)O_(3)(s),Fe(s),H_(2)O(l),H_(2)(g)),(C_(P)^(@)(JK^(-1)mol),103.0,25.0,75.0,28.0):}`

Explanation

`Fe_(2)O_(3)(s) +3H_(2) rarr 2Fe +3H_(2)O`
`DeltaC_(P) = (C_(P)) (Product) - (C_(P)) (Reactant)`
`=(2 xx 25.0 +3 xx 75.0) - (103.0 +3 xx 28.0)`
`= 275.0 - 187.0 = 88.0J`
`(DeltaH_(T_(2))-DeltaH_(T_(1)))/(T_(2)-T_(1)) = DeltaC_(P)`
`(DeltaH_(558) -(-33.0))/(359-298) = 88.0 xx 10^(-3)`
`DeltaH_(358) =- 27.72kJ mol^(-1)`