Ethanol was oxidised to acetic acid in a catalyst chamber at `18^(@)C`. Calculate the rate of removel of heat to maintain the reaction chamber at `18^(@)C` with the feed rate of `30 kg h^(-1)` ethanol along with excess oxygen to the system at `18^(@)C`, given that a `42 mol%` yield based on ethanol is obtained. Given that
`Delta_(f)H^(Theta)underset(H_(2)O)'(l) =- 68.0 kcal mol^(-1)`
`Delta_(f)H^(Theta)underset(C_(2)H_(5)OH)'(l) =- 66 kcal mol^(-1)`
`Delta_(f)H^(Theta)underset(CH_(3)COOH)'(l) =- 118 kcal mol^(-1)`

Explanation

`C_(2)H_(5)OH + O_(2) rarr CH_(3)COOH + H_(2)O`
`DeltaH^(Theta) = sum_(f)H^(Theta) (Product) - sum_(f)H^(Theta)(Reactant)`
`=(-118 - 68.0) -(-66)`
`=- 120.0 kcal`
Yield is `42%`. Thus, enegry producted per hour will be
`= (120.0 xx 42xx30000)/(100xx46) = 32869 kcal k^(-1)`