The value of `DeltaH_(O-H)` is `109 kcal mol^(-1)`. Then formation of one mole of water in gaseous state from `H(g)` and `O(g)` is accompanied by

Options

A. Release of `218 kcal` of enegry
B. Release of `109 kcal` of enegry
C. Absorption of `218 kcal` of enegry
D. Unpredicatable

Answer

A

Explanation

`H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g)`
`DeltaH =- (2 xx Delta_(O-H)H^(Theta))`
`DeltaH =- 2 xx 109 =- 218 kcal`