Equal volumes of `1M HCI` and `1M H_(2)SO_(4)` are neutralised by `M NaOH` solution and `x` and `y kJ//` equivalent of heat are liberated, respectively. Which of the following relations is correct?

Options

A. `x = 2y`
B. `x = 3y`
C. `x = 4y`
D. `x = (1)/(2)y`

Answer

D

Explanation

Since, `H_(2)SO_(4)` gives `2 "moles" H^(o+), HCI` gives `1"mole" H^(o+)` from 1mole after ionisation. Hence, `H_(2)So_(4)` will release double amount of heat as compared to `HCI`.
i.e., `y = 2x or x = (y)/(2)`