Enthalpy of neutralisation of the reaction between `CH_(3)COOH(aq)` and `NaOH(aq)` si `-13.2kcal Eq^(-1)` and that of the reaction between `H_(2)SO_(4)(aq)` and `KOH (aq)` is `-13.7 kcal Eq^(-1)`. The enthalpy of dissociation of `CH_(3)COOH(aq)` is

Options

A. `-0.5 kcal Eq^(-1)`
B. `+0.5 kcal Eq^(-1)`
C. `-26.9 kcal Eq^(-1)`
D. `+13.45 kcal Eq^(-1)`

Explanation

To find the enthalpy of dissociation of acetic acid (CH₃COOH), we can use the relationship between the enthalpy of dissociation and the enthalpy of neutralization. The enthalpy of neutralization is the heat change that occurs when an acid and a base react to form water and a salt.

### Step-by-Step Solution:

1. **Identify the Given Data**:
- Enthalpy of neutralization for the reaction between acetic acid (CH₃COOH) and sodium hydroxide (NaOH) = -13.2 kcal/eq.
- Enthalpy of neutralization for the reaction between sulfuric acid (H₂SO₄) and potassium hydroxide (KOH) = -13.7 kcal/eq.

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