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If the enthalpy of combustion of C(graph...

If the enthalpy of combustion of `C`(graphite) is `-393.3kJ mol^(-1)`, then for producing `39.3kJ` of heat the amount of carbon required is

A

`1.5 mol`

B

`0.5mol`

C

`1.2 g`

D

`12 mg`

Text Solution

Verified by Experts

`393.3 kJ` enegry produced by `12 gC`
Therefore, `39.3 kJ` enegry produced by `(12 xx39.3)/(393.3) = 1.2 g of C` (graphite)
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