The ethalpies for the following reactions at `25^(@)C` are given as:
`(1)/(2)H_(2)(g)+(1)/(2)O_(2)(g) rarr OH (g), DeltaH = 10.06 kcal`
`H_(2)(g)rarr 2H(g),DeltaH = 104.18 kcal`
`O_(2)(g) rarr 2O(g),DeltaH = 118.32 kcal`
Calculate the `O-H` bond enegry in the `OH` group.

Explanation

Required equation is
`H(g) +O(g) rarr O-H(g),DeltaH = ?`
Given
`(1)/(2)H_(2)(g) +(1)/(2)O_(2)(g) rarr OH(g),DeltaH =+ 10.06 kcal`
`H(g) rarr (1)/(2)H_(2)(g),DeltaH =- 52.0 kcal`
`O(g)rarr (1)/(2)O_(2)(g),DeltaH =- 59.16 kcal`
Adding, we get
`H(g)+O(g) rarr OH(g),DeltaH =- 101.19 kcal`