A carnot engine operates between temperature `600 K` and `300 K`. It absorbs `100 J` from the source. Calculate the heat transferred to the sink.

Explanation

Using: `eta_("Carnot") =1 - (T_(1))/(T_(2)) =1- (300)/(600) = (1)/(2) = 50%`
Also, `eta_("carnot") = ("Work done")/("Heat abosorbed") = ("Work done")/(100)`
`rArr` Work done `=100 xx (1)/(2) = 50 J`
and the heat lost to the surrounding `=100 - 50 = 50 J`