Heat supplied to a Carnot egine is `453.6 kcal`. How much useful work can be done by the engine that works between `10^(@)C`and `100^(@)C`?

Explanation

`T_(2) = 100 +273 = 373 K , T_(1) = 10 + 273 = 283K,`
`q_(2) = 453.6 xx 4.184 = 1897.86 kJ`
We know that
`w = q_(2).(T_(2)-T_(1))/(T_(2))`
`= 1897.86 xx ((373-283))/(373)`
`= (1897.86 xx 90)/(373) = 457.92 kJ`