Calculate the entropy change `(DeltaS)` when `1 mol` of ice at `0^(@)C` is converted into water at `0^(@)C`. Heat of fusion of ice at `0^(@)C` is `1436 cal` per mol.

Explanation

Entropy change `(DeltaS)` for the change of state of a substance is given by dividing the heat change by the absolute temperature at which the change takes place reversibly, i.e., at the melting point in this case.
Hence, `DeltaS = (q_(rev))/(T) = (1436)/(237) = 5.26 cal deg^(-1) mol^(-1)`