Calculate the enthalpy of vaporisation per mole for ethanol. Given `DeltaS = 109.8 J K^(-1) mol^(-1)` and boiling point of ethanol is `78.5^(@)`.

Explanation

To calculate the enthalpy of vaporization per mole for ethanol, we can use the relationship between entropy change (ΔS) and enthalpy change (ΔH) at the boiling point (T) of the substance. The formula we will use is:

\[ \Delta S = \frac{\Delta H}{T} \]

Where:
- ΔS is the change in entropy (given as 109.8 J K⁻¹ mol⁻¹)
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