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Melting point of a solid is xK and its l...

Melting point of a solid is `xK` and its latent heat of fusion is `600 cal mol^(-1)`. The entropy changes for fusion of `1 mol` solid is `2 cal mol^(-1) K^(-1)`. The value of `x` will be

A

`100K`

B

`200K`

C

`300K`

D

`400K`

Text Solution

Verified by Experts

`(Delta_(fustion)H^(Theta))/(T_(mp)) = Delta_(fustion)S^(Theta)`
`(600)/(T) = 2`
`T = 300 K`
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