`DeltaH` and `DeltaS` for
`Br_(2)(l) +CI_(2)(g) rarr 2BrCI(g)`
are `29.00 kJ mol^(-1)` and `100.0 J K^(-1) mol^(-1)` respectively. Above what temperature will this reaction become spontaneous?

Explanation

Accroding to Gibbs-Helmholtz equation,
`DeltaG = DeltaH - T DeltaS`
For spontaneous process, `DeltaG lt 0`
i.e., `DeltaH - T DeltaS lt 0`
`T DeltS gt DeltaH`
`T gt (DeltaH)/(DeltaS)`
`T gt (29.0xx1000)/(100)`
`T gt 290 K`