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Using .(f)G^(Theta)(Hi) = 1.3 kJ mol^(-1...

Using `._(f)G^(Theta)(Hi) = 1.3 kJ mol^(-1)`, calculate the standard free enegry change for the following reaction:
`H_(2)(g) +I_(2)(g) rarr 2HI(g)`

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`DeltaG^(Theta) = sum_(f)G^(Theta) ("products") -sum_(f)G^(Theta)("reactants")`
`= 2xx(1.3) -(0+0)`
`= 2.6 -0 = 2.6 kJ mol^(-1)`
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